In the Byteotian Line Forest there are trees in a row. On top of the first one, there is a little bird who would like to fly over to the top of the last tree. Being in fact very little, the bird might lack the strength to fly there without any stop. If the bird is sitting on top of the tree no. , then in a single flight leg it can fly to any of the trees no.i+1,i+2…I+K, and then has to rest afterward.
Moreover, flying up is far harder to flying down. A flight leg is tiresome if it ends in a tree at least as high as the one where is started. Otherwise the flight leg is not tiresome.
The goal is to select the trees on which the little bird will land so that the overall flight is least tiresome, i.e., it has the minimum number of tiresome legs. We note that birds are social creatures, and our bird has a few bird-friends who would also like to get from the first tree to the last one. The stamina of all the birds varies, so the bird's friends may have different values of the parameter . Help all the birds, little and big!
有一排n棵树,第i棵树的高度是Di。
MHY要从第一棵树到第n棵树去找他的妹子玩。
如果MHY在第i棵树,那么他可以跳到第i+1,i+2,...,i+k棵树。
如果MHY跳到一棵不矮于当前树的树,那么他的劳累值会+1,否则不会。
为了有体力和妹子玩,MHY要最小化劳累值。